Water weighs 62.5lbs\ft. to the 3rd power. How much does the water in a full 5ft by 3ft by 2ft rectangular fish tank weigh?
2006-09-13 12:33:35 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Compute the volume and multiply by the weight
5*3*2 *(62.5)
30*62.5 lb
1,875 lb
2006-09-13 12:35:08 · answer #1 · answered by odu83 7 · 0⤊ 0⤋
To find the volume of water, multiply the length, width and height of the tank (5x3x2). That will be how many cubic feet of water are in the tank. Then multiply that result by 62.5 to get the weight in pounds.
2006-09-14 23:25:53 · answer #2 · answered by Billy 1 · 0⤊ 0⤋
volume of fish tank, 5ft times 3ft times 2ft= 30cu ft. then multiply the volume, 30cu ft. by the weight of a cu ft of water, 62.5 lb and you get the answer. 1875lb
2006-09-13 19:47:20 · answer #3 · answered by canoe 1 · 0⤊ 0⤋
Are you sure that is to the 3rd power?if it is here it go.
If you want to find the answer first multuply 5 by 3 then by 2. then cube the 62.5 and multiply your first answer by the second answer.
5*3*2=30
62.5^3=244140.625(wich I still think you got it wrong)
30*244140.625=7324218.75
2006-09-13 19:41:50 · answer #4 · answered by enano 4 · 0⤊ 0⤋
you first need to find the total cubic feet which would be 5 * 3 * 2 or 30 Cubic feet.
Then multiply 30 * 62.5 ^ 3
2006-09-13 19:36:16 · answer #5 · answered by j H 6 · 0⤊ 0⤋