I have a 12oz. solution of 3.5% alcohol and a 1.7oz. solution of 12% alcohol. What is the percentage of alcohol in their mixture?
DO NOT ANSWER!!
JUST GIVE ME THE FORMULA PLEASE!
2006-09-13 11:52:20 · 6 answers · asked by Ichigo204 3 in Science & Mathematics ➔ Mathematics
12(3.5) + 1.7(12) = (12+1.7)(x)
Answer: x%
2006-09-13 11:57:00 · answer #1 · answered by MsMath 7 · 1⤊ 1⤋
Here is how you would handle this: When you mix these two together let x equal the percentage of the mixture that is 3.5% alcohol( 12/13.7) and y equal the percentage of the mixture that is 1.7% alcohol (1.7/13.7). Here is the formula which will show you the new percentage: X*3.5% + Y *1.7%
2006-09-13 11:59:07 · answer #2 · answered by bruinfan 7 · 1⤊ 0⤋
Good for you.
Find out how much alchohol is in each separately (by multiplying total by percentage), and add those together.
Add up the total volume of the final mixture.
Divide the amount of alchohol by the total amount of mixture.
Don't forget to move the decimal point over for a percentage!
If you actually wanted a formula...
Let there be "a" units of an "x" percent solution and "b" units of "y" percent.
100(.01ax+.01by)/(a+b) is the percentage of the final solution.
2006-09-13 11:56:55 · answer #3 · answered by Mehoo 3 · 3⤊ 1⤋
Lancenigo di Villorba (television), Italy YOUR answer IS 40 8% weight expressed for Cu2O. You despatched me the "Dry Weight" of a copper oxides mixture. I write a mathematical relation, right here : a million.541 = x * 142 + y * seventy 9 the place x and y are variety of moles respectively for Cu2O (e.g. cuprous oxide, molar weight as 142) and for CuO (e.g. cupric oxide, molecular weight as seventy 9). you positioned this blend in a closed vessel for a hydrogenation technique, as follows : Cu2O(s) + H2(g) ---> 2 Cu(s) + H2O(l) CuO(s) + H2(g) ---> Cu(s) + H2O(l) You dried the unconventional count number and you retrieve in basic terms metalic copper (molar weight as sixty 3) in a 2nd mathematical relation as follows : a million.295 = x * 126 + y * sixty 3 you have 2 mathematical situations for 2 mathematical unknown words. Your recommendations are x = 0.0052 moles (e.g. Cu2O as 0.738 g or 40 8%) y = 0.0102 moles (e.g. CuO as 0.804 g or fifty two%) i desire this enables you.
2016-09-30 22:24:22 · answer #4 · answered by ? 4 · 0⤊ 0⤋
Find the number of ounces in each portion. Add them together, then divide by the total volume of the final solution.
2006-09-13 11:56:54 · answer #5 · answered by Anonymous · 2⤊ 1⤋
take the weighted average:
(12 x 3.5% + 1.7 x 12%)/(12+1.7)
2006-09-13 11:57:30 · answer #6 · answered by mitch_online_nl 3 · 1⤊ 0⤋