Help? Could you explain
-2h
-------
x(x+h)
-------------
h
2006-09-13 11:08:55 · 6 answers · asked by carolinacavs88 1 in Science & Mathematics ➔ Mathematics
the h on the top cancels with the h on the bottom and you are left with -2/(x(x+h))
So when h goes to zero, you have
-2/(x(x+0)) = -2/(x(x)) = -2/x^2 which is the derivative of 2/x
2006-09-13 11:12:09 · answer #1 · answered by MsMath 7 · 1⤊ 0⤋
That is sooooo easy, I don't believe you need to ask. The h in the numerator cancels (i.e., -2h becomes -2). You should study more instead of getting answers here.
2006-09-13 18:12:27 · answer #2 · answered by nuclear_science 3 · 1⤊ 0⤋
The h in the numerator would cancel with the h in the denominator, leaving -2/x(x+h).
2006-09-13 18:13:16 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋
Multiply top and bottom by 1/h
You get -2/[x(x+h)]
I saw no limit as h approached zero.
2006-09-13 18:19:35 · answer #4 · answered by Anonymous · 0⤊ 0⤋
-2h x h
_______
x (x + h)
-2h^2
_______
x^2 + hx
1
____________
x^2 + hx + 2h^2
1
___________
(x + 2h)(x - h)
2006-09-13 18:31:17 · answer #5 · answered by tragictrust 2 · 0⤊ 0⤋
What do you want explained?
2006-09-13 18:10:48 · answer #6 · answered by limgrn_maria 4 · 0⤊ 1⤋