Your partitions of four are given by (1, 1, 1, 1) (1 version), (1, 1, 2) (3 versions), (2, 2) (1 version), and (1, 3) (2 versions). Each version is a different partition (ways to express 4 as a sum), so your answer is 1+3+1+2 = 7. Specifically (1+1+1+1), (1+1+2), (1+2+1), (2+1+1), (2+2), (1+3), and (3+1).
2006-09-13 11:07:12
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answer #1
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answered by maegical 4
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My answer would be 8.
0+4
4+0
1+3
3+1
2+2
1+1+1+1
2+1+1
1+2+1
1+1+2
2006-09-13 18:07:19
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answer #2
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answered by Anonymous
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