Heat and energy question?

Question

How much heat energy is given out when 300ml of 0.1 M NaOH solution is reacted with sufficient HCl solution.

NaOH(aq) + HCl(aq) <-> NaCl(aq) + H2O(aq) ?H= -56.2kJ/mol NaOH


And assuming that the volume of the solution after reaction is 600 mL, with mass 600g and the initial temperature of the solution was 25°C. Also assuming that the heat capacity of the solution is the same as of water -= 4.184 J/g/K. What is the final temperature of the solution after the reaction.

Answer 1

I know I shouldn't do your HW for you, but I'll show you hows its done and assume you'll learn something from it.

300mL * 0.1M NaOH = 0.03 mol NaOH

0.03 mol NaOH * (56.2kJ/mol NaOH) = 1.686 kJ heat released

Using the equation Q = m*Cp*deltaT

deltaT = 600g*4.184J/g-K / 1686J = 1.49 oC

Tf = 25oC + 1.49 oC = 26.49 oC