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I have no idea how to go about solving this problem........I tried, and I'm completely lost...

"The depth of water behind the Hoover Dam is 220m. What is the water pressure at the base of this dam? (ignore the pressure due to the atmosphere)

2006-09-13 09:42:45 · 8 answers · asked by Anonymous in Science & Mathematics Physics

8 answers

P = Po + pgh

P = pgh

p is the greek letter, rho, and stands for the density or water

P = (1)(9.81)(220)

P = 2.16 x 10^3 Pa or 2.13 x 10^(-5) atm


* Ignore the solutions that other people are giving you. I showed you how your teacher wants to see it.

2006-09-13 09:49:54 · answer #1 · answered by عبد الله (ドラゴン) 5 · 0 0

The question must want you to ignore the fluid pressures coming from any possible flow of water too since these are not mentioned. You are therefore just dealing with a question on Hydrostatics. This purely relates to the weight of the water above you. In the case where the fluid is at rest, called fluid statics or hydrostatics (from hydro meaning "water" and static meaning "at rest"), the force acting on the object is the sheer weight of the fluid above, up to the water's surface—such as from a water tower. The resulting hydrostatic pressure (static pressure) is isotropic: the pressure acts in all directions equally, according to Pascal's law:


where:

ρ (rho) is the density of the fluid (the practical density of fresh water is 1000 kg/m3);
g is the acceleration due to gravity (practical value 10 m/s2 );
h is the height of the water column in metres.
In the following example. Assume a water column 1 metre high, the pressure on the floor of the column will be:

Pa.
The pressure increases linearly with the water depth.

2006-09-13 16:55:29 · answer #2 · answered by swf77uk 2 · 0 0

Enter into Yahoo search the question:what is the water pressure at the base of Hoover Dam. You will get an excellent answer.

2006-09-13 16:51:40 · answer #3 · answered by icare4you 2 · 0 0

Pressure = density * acceleration due to gravity * height or depth of fluid. Use the same units throughout. Given the depth is in Meters, use S I Metric throughout. Given the number of significant digits is 3, use that for all units. That is as close an answer possible. Density of water = 1 gram / cubic cm. Convert to Kg / cubic Meters. Acceleration due to gravity is 9.81 Meters per second per second. Depth is given in the problem. Neglecting atmospheric pressure means do not add it to the equation.

2006-09-13 17:35:22 · answer #4 · answered by Jack 7 · 0 0

The quick trick is just think of a tube with 1 sqare cm cross section, and get the weight of the water in that tube if it was 220m long.

2006-09-13 19:08:27 · answer #5 · answered by Ken H 4 · 0 0

Every 10 metres of water exerts approx 1 bar of pressure, thus if you ignore pressure caused by the atmosphere, then its 22 bar - but since atmospheric pressure is 1 bar (approx) then the total pressure is 23 bar.

1 bar = 14.50377lb/psi = 750.0638 mmHg

2006-09-13 16:48:31 · answer #6 · answered by Richard W 4 · 2 0

Depend on the the type of pressure gauge you use.
pressure will be 22 bar if you use gauge pressure indicator.
pressure will be 23 bar if you use absolute pressure indicator.

2006-09-13 20:52:18 · answer #7 · answered by dwarf 3 · 0 0

Force =mgh where m= volume of water x density=areax height x1(because density =1)
Pressure =force per unit area
=Force/area
={areax9.8x220}/area=9.8x220=2156 units

2006-09-13 16:57:48 · answer #8 · answered by Amar Soni 7 · 0 0

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