can you answer my math question?

Question

a2= a squared y3 = y cubed...

a2-y3(a-y2)y2 If a = -2 and y =-3

please help me I am having a very difficult time, and please show all work so i know how you did it.

Answer 1

First it might be easier for you to see the equation as (as long as you typed it out correctly):

a^2-y^5(a-y^2) : since the power of y^3 (y cubed) and y^2 (y squared) are "added" when two powers are multiplied.

now subsitute the values of a and b:
= (-2)^2 - (-3)^5[(-2) - (-3)^2]
= (-2)(-2) - (-3)(-3)(-3)(-3)(-3)[(-2) - (-3)(-3)] : I've put this here so you can see how the powers multiply out
= 4 - (-243)[(-2) - 9] : remember that 4 - (-243) is actually 4 + 243
= 4 + 243(-11)
= -2669

Answer 2

Everywhere there is an A you plug in -2 and y you put in -3

(-2)2-(-3)3(2-[-2]2)-2(2) --I'm sorry for the mess, try as best you can to follow along

Use PEMDAS--Parentheses, Exponents, Multiplication/Division, Addition/Subtraction

-2-4=-6 what's in the parentheses

(-2)2-(-3)3*-6*4 process simplified after parentheses are gotten rid of

(-2)2=4 -2*-2=4 negative times negative equals positive

(-3)3=-27 negative 3 times negative 3= positive 9. positive 9 times
negative 3= negative 27

(-3)2=9 negative 3 times negative 3=positive 9

4-27*-6*9 simplified down, you now go to multiplication/division

(-27*-6*9)+4 moved 4 to the other side to make it easier, it is positive so you will add it

(1458)+4 multiplying those numbers gave negative 27 times negative 6=positive 162
positive 162 times positive 9=positive 1458

1458+4=1462

so the answer is 1462

Answer 3

Just write the equation and substitute in the numbers.

if a = -2, then (-2)2-y3(-2-y2)y2 and solve for y

for y=-3, then a2-(-3)3(a-(-3)2)(-3)2 and solve for a

Or are you looking to substitute both at the same time?

Answer 4

replace all y w/ (-3) and all a w/ (-2)

(-2)2 - (-3)3 ((-2)-(-3)2) (-3)2

do all the squares and cubes 1st=

(-2)*(-2)=4
(-3)*(-3)*(-3)=-27
(-3)*(-3)=9

now enter totals into equation

4-(-27)((-2)-9)9

do original parenthesis first
( -2-9)= -11

now u have
4 - (-27)(-11)9

now do multiplication

-27 * -11 * 9= 2673

now...

4-2673= -2669

that should be ur answer. remember to always replace the letters w/ their totals 1st, putting them into parenthesis if if there is a negative sign helps. then figure all ur cubes n squares. the goal is to try to get basic numbers. then do the equations in parenth. so ur problem ends up w no letters, cubes/squares, and parenthesis. then solve! hope that helped!

Answer 5

a^2-y^3(a-y^2)y^2 {a^2 means a squared, y^3 means b cubed}

(-2)^2-(-3)^3[-2-(-3)^2] (-3)^2
= 4-(-27)[-2-9](9)
=4+27(-11)(9)
=4-2673
= -2669

Answer 6

^2 means power of 2 ^3 power of 3
-2^2+y^3(-2--3^2)-3^2
4+27(-2-9)9
31(-11)9
9+31=40
40(-11)
40x-11
=
-440
plz give me a gd ratin i spent ages ova this

Answer 7

(-2)^2-(-3)^3{(-2)-(-3)^2}(-3)^2
=4-(-27)(-11)(9)
=4-2673=-2669

Answer 8

is that calculus?? cuz i need help too.. arrggg!! i hate math!!

Answer 9

im sorry im not that smart

Answer 10

so sorry, I HATE math!