Two guys are tossing coin with a bet of $1 for each game. After some tosses., one guy earned $3 while the other won three times. How many games do they
2006-09-13 07:50:12 · 6 answers · asked by santosh 1 in Education & Reference ➔ Higher Education (University +)
they played nine times... The other guy won three, which means the first guy lost $3... for the first guy to break even they'd have to play another 3 and for him to earn $3 another 3 games, so, nine games total...
2006-09-13 08:00:22 · answer #1 · answered by Vince has left the building... 5 · 0⤊ 0⤋
3
2006-09-13 14:53:09 · answer #2 · answered by Pinada 3 · 0⤊ 1⤋
Nine (9). Call the boys A and B. B won the first three games and lost the next three. He is even on bets after six games have been played. He then loses the next three games so he has lost $3.
A lost the first three games but won the next three. He is even on bets after six games. He then wins the next three. He wins $3.
2006-09-13 14:59:49 · answer #3 · answered by thomasrobinsonantonio 7 · 0⤊ 0⤋
They player 6 times.
2006-09-13 14:52:57 · answer #4 · answered by MrRSMan 2 · 0⤊ 1⤋
3?
2006-09-13 14:52:24 · answer #5 · answered by Genio Atrapado 5 · 0⤊ 1⤋
3 because one guy earned his and not won by the game..tada...give me my 10 points.
2006-09-13 14:59:18 · answer #6 · answered by Anonymous · 0⤊ 1⤋