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4 answers

435

2006-09-13 06:58:10 · answer #1 · answered by Sai♥Pranav 3 · 0 1

TWO HUNDRED AND SIXTY FIVE (265)
two hun-D(500)re-D(500)
an-D(500)
sIX(9)ty
fIV(4)e
pL(50)us
45 (45)
5 (5)
tIM(999)es
25 (25)

So it should be:
265 + 500 + 500 + 500 + 9 + 4 + 50 + 45 + 5 + 999 + 25

Answer:
2902*

*however, the problem isn't that clearly stated, so who knows if you expect us to count all the combinations (e.g. individual digits, or the value of written equations such as 5 x 25, etc.)

2006-09-13 07:13:22 · answer #2 · answered by cg-productions 4 · 0 0

435, or CDXXXV

2006-09-13 07:02:01 · answer #3 · answered by Paul 7 · 0 0

no way
do it yourself

2006-09-13 06:59:58 · answer #4 · answered by friend 3 · 0 0

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