What is the tension in the rope and the horizontal force exerted on the ground?

Question

In a tug-of-war between two athletes, each pulls on the rope with a force of 999 N. What is the tension in the rope? What is the absolute value of the horizontal force that each athlete exert against the ground?

Answer 1

Since the rope is not accelerating, the net force on the rope is zero; otherwise, one side or the other would be winning and the rope would be accelerating and moving in the winning side's direction.

Further, since neither team is moving, the net forces on each one must also be zero. The only way that can be is for each team to be exerting 999 N of force in the opposite direction to the 999 N tension on the rope.

The key to working this problem is in recognizing that none of the system (rope, two teams) is moving; so there is no acceleration, which we must have if the net force is other than zero. So we simply add up all the included forces to make sure they do in fact add up to zero overall.

Answer 2

The tension in the rope is 999*2N this tension is absorbed by the rope fiber. This is why the rope must be strong enough. If the force on the rope is zero then any rope can do the trick. Now the net force on the rope is zero i.e. the external force is equal to the internal force hence no movement. Each team exert 999N on the floor this force is opposed by a force exerted by the floor in the form of friction force and this is also in equilibrium i.e. the external force is equal to the internal force.Now the entire system men rope and ground is in equilibrium.

Answer 3

in the event that they're the two pulling on the rope with 250N, the rigidity interior the rope is 250*2 = 500N. If the physics varieties are not shifting, they're in equilibrium, so the horizontal stress the rope is exerting on them ought to be balanced with an equivalent horizontal reaction stress from the floor (ie. 250N for each physicist.)

Answer 4

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