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how to lose this one

2006-09-13 04:56:56 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

How can be integrated by parts??

2006-09-13 05:22:12 · update #1

4 answers

I have not a clue. I work at a college and am getting in touch with a math professor will post back in a while

2006-09-13 05:10:42 · answer #1 · answered by scokeman 4 · 0 0

assuming this is dy/dx + (ln x)/[3x (2 - ln x)] = 0
then, dy/dx = -(ln x) / [6x - 3x.ln x]
now seperate the variables and integrate.

2006-09-13 05:09:10 · answer #2 · answered by yasiru89 6 · 0 0

put t = ln x
dt/dx = 1/x
dt = 1/x dx

substitute in given equation

dy/dx +( t/(2-t)^3 =0
dy/dx = -t/(2-t)^3
dy/dx = dy/dt/(dx/dt) = xdy/dt= e^tdy/dt

dy/dt = -e^(-t)/(2-t)^3
now it can be integrated by parts

2006-09-13 05:04:49 · answer #3 · answered by Mein Hoon Na 7 · 0 0

Please writ it in brackets so that it can be expanded

2006-09-13 05:06:43 · answer #4 · answered by Amar Soni 7 · 0 0

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