draw acceleration-mass graph keeping the force constant?

Answer 1

Given, force, F is constant. Assuming mass m can be varied, how does acceleration a vary?

The mutual relation is F = m.a or a = F/m.
Since F is constant, acceleration a is proportional to 1/m; i.e. reciprocal of m. If mass is increased, acceleration will decrease and vice versa. The graph of a versus m is a curve meeting the m axis at infinity. Well, I can't draw the graph as I am not sure about using the drawing facility here.

Answer 2

It feels like you're concerning one certain graph. A graph is only a pictoral representation of recommendations, meaning we may be able to amplify both axis (F or A, for this reason) so some distance as we favor. you're honestly correct in that once (a)=0, F=0, and to that end the point (0,0) can fairly (and properly) be protected on your graph. If the graph you're searching at does not bypass as low as 0 on both axis, it would want to be the case that this area of 0-acceleration should not be suitable to the priority you attempt to remedy.

Answer 3

if you are talking about non relativistic cases and constant mass it will be a single point coordinates (m,F/m) in case of a relativistic situation the mass will increase as speed rises thus it willbe a horrible graph as increasing mass will subdue the acceleration which will tend to zero so it will becone asymptotic to the mass axis as we go towards infinity on the axis of mass

Answer 4

WELL......IN NORMAL CASES THE MASS DOES NOT VARY...
BU IF U R TALKING OF CONDITIONS WHERE VELOCTY OF THE PARTICLE....IS CLOSE TO VELOCITY OF LIGHT THAN THE CURVE WOLD B AN INVERSE.HYPERBOLA....I HAVE NO STANDARD NAME 4 THE FUNCTION...THE EQUATIONWILL B REPROCICAL OF STANDARD HYPERBOLA EQUATION..

Answer 5

How do i draw a line here?

Answer 6

F = ma so F/a = m (Hint: It's a hyperbola ☺)


Doug

Answer 7

It will be ractanguler hyperbola