Surely the clean living Paul McC.....as long as Heather Mills doesn't put his blood pressure up too high and give him a stroke or something.
2006-09-13 04:10:31
·
answer #1
·
answered by Anonymous
·
0⤊
0⤋
It's going to be Ringo. Poor Paul probably lost 20 years off his life by getting married to Heather Mills who must be the stupidest woman on the face of the earth. How does one manage to snag the most eligible and probably most loving billionaire on the face of the earth and cannot make it work because you're ambitious and argumentative? What planet did she come from? Poor Paul. But then again, serves him right too, for thinking with his d...k and marrying a bimbo 30 years younger than him. Why couldn't he have chosen someone closer to his own age?
2006-09-13 11:18:12
·
answer #2
·
answered by Cassandra 3
·
1⤊
0⤋
The walrus was Paul, but the walrus is supposedly a symbol of death.
I think it will be Ringo!
2006-09-13 11:10:56
·
answer #3
·
answered by frank z 2
·
0⤊
1⤋
Ringo will. He didn't excess in the early years like Paul did.
2006-09-13 11:13:49
·
answer #4
·
answered by Tangus 4
·
0⤊
1⤋
I feel that since we only have two of the most music geniuses left in our world why ask?
Lets just hope these icons are around for a long, long, long time!
The walrus was dead, it was a real drug time back then I think it was written in reference to that.
2006-09-13 11:17:35
·
answer #5
·
answered by I love angels 2
·
0⤊
1⤋
Studies show married me live longer - it will be Ringo.
2006-09-13 11:23:16
·
answer #6
·
answered by Queen of Cards 4
·
1⤊
0⤋
The least relevant, so I'm figuring Ringo. No offence to him, mind you - I'm guessing he wouldn't mind living the longest. :-)
2006-09-13 11:12:56
·
answer #7
·
answered by valerie h 2
·
0⤊
0⤋
Paul!
2006-09-13 11:17:48
·
answer #8
·
answered by GirlsRGamers2 7
·
0⤊
1⤋
Paul McCartney, a great musician with a great vision.
2006-09-13 11:13:48
·
answer #9
·
answered by ideaquest 7
·
1⤊
1⤋
paul's dead so it has to be ringo.
2006-09-13 11:41:06
·
answer #10
·
answered by liberpez 5
·
0⤊
2⤋