A car with an initial speed of 23.7 km/h accelerates at a uniform rate of 0.92 m/s(squared) for 3.6 s. Find the final speed and the displacement of the car during this time.
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2006-09-13 03:44:48 · 6 answers · asked by itink3 1 in Education & Reference ➔ Homework Help
vf = vi + at
where vf is final velocity, vi = initial velocity.
vi = 23.7 km/h = 23700 m / 3600 sec = 6.58 m/s
vf = 6.58 m/s + .92 m/s^2 * 3.6s
vf = 9.892 m/s
d = vit + 1/2at^2
d = 23.7 * 3.6 + 1/2 * .92 * 3.6^2
d = 85.32 + 5.96
d = 91.28 m
2006-09-13 03:52:57 · answer #1 · answered by ³√carthagebrujah 6 · 1⤊ 0⤋
For the moment, ignore the initial speed. Now, multiply the acceleration times the elapsed time. Convert that answer from m/s to m/hr. and then to km/hr. Add that speed to the initial speed to find the final speed.
2006-09-13 03:55:00 · answer #2 · answered by tom_terrific73 4 · 0⤊ 0⤋
First convert 23.7km/h into m/s i.e 23.7* 5/18= 6.58 m/s.
initial speed u = 6.58m/s, a = 0.92, t = 3.6 s
a = v -u / t
0.92 = v - 6.58 / 3.6.
0.92 * 3.6 + 6.58 =v
v = 9.89
v^2 = u^2 + 2as
( 9.81) ^2 = (6.58)^2 + 2(0.92 )s
s = 54.52 /2* 0.92
= 29.63 m
I have not shown the multiplicationsbut tried to make the things simple.
2006-09-13 06:23:47 · answer #3 · answered by macline k 2 · 0⤊ 0⤋
dist= Initial speed + 1/2 Acc~n * time (squared)
u do the math & make sure u change the Km/hr to m/sec
2006-09-13 03:52:45 · answer #4 · answered by Anonymous · 0⤊ 0⤋
carthageb... is correct in is calculations.
2006-09-13 04:14:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Please visit the following sites:
http://id.mind.net/~zona/mstm/physics/mechanics/mechanics.html
or
2) http://www.wiley.com//college/cutnell/mod/#chap02
2006-09-13 04:05:08 · answer #6 · answered by baby 1 · 0⤊ 0⤋