Jan has 4 kids. Joey, Britt, Candle, and Harry. Each morning Jan puts something special in their lunch box. On this morning she was following a specific request from John, the husband. John had given Jan 4 specific items to give each kid. Joey was into baseball, so dad had picked out a pack of baseball cards for him. Britt was into horses, so dad had picked out a small ceramic pony for her. Candle was a big hockey fan, so he had a puck for her. Harry was a big fan of Twisted Sister, so he had a music CD for him. Jan had many things on her mind on the morning of the mistake. She gave each of the kids their lunch boxes, and after they had left she second guessed who got what. She did give one gift to each kid. What are the chances that exactly 3 of the kids got the correct gift? In %.
2006-09-13 02:08:00 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
zero chances if she had switched a box then definetly the other one is also false therefore she would have given correctly to all the four or atleast two of them and three has no room at all.
2006-09-13 02:13:12 · answer #1 · answered by ssmindia 6 · 0⤊ 0⤋
0 if she made the mistake with one then obviously then another child was given a wrong gift so then 3 children could not get the right gift...
2006-09-13 09:35:27 · answer #2 · answered by robert m 2 · 0⤊ 0⤋
The percentage chance isn't 0 if in one of the lunch boxes she accidently put a big vibrating dildo instead of say... the pack of baseball cards...
2006-09-13 13:12:55 · answer #3 · answered by Andy J 2 · 0⤊ 0⤋
If 3 kids got the correct gift...wouldn't the fourth one also get the correct gift?
2006-09-13 09:13:45 · answer #4 · answered by Emporer_Smiley 2 · 0⤊ 0⤋