here's another problem in geometry...?

Question

pls help me to answer this problem and i'll do the rest of my homeworks...

solve for "a".

3x+square root of 4 all over 5 & 5x-square root of 8 all over 3

pls answer this and explain so that i can understand and do the rest of my homeworks in geometry....

pls and tnx in advance and i love you all!!!!!

Answer 1

I think this is what you're describing:

(3x + √4) / 5 + (5x - √8) /3 = 0

Step 1: Find a common denominator.
(3x + √4) / 5 * 3/3 + (5x - √8) /3 * 5/5 = 0
3(3x + √4) / 15 + 5(5x - √8) /15 = 0
(9x + 3√4 + 25x - 5√8) / 15 = 0

Step 2: Multiply both sides by 15 to get rid of the denominator:
(9x + 3√4 + 25x - 5√8) / 15 * 15 = 0 * 15
(9x + 3√4 + 25x - 5√8) = 0

Step 3: Combine like terms:
(9x + 3√4 + 25x - 5√8) = 0
(9x + 25x + 3√4 - 5√8) = 0
(36x + 3 * 2 - 5√8) = 0
(36x + 6 - 5√8) = 0
(36x - 8.142) = 0
36x = 8.142
x = .226

Answer 2

This is not geometry....this is Algebra and pls be more specific....what do you mean by ''all over'' and solve 'a'....there is no 'a'