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2006-09-12 19:57:38 · 8 answers · asked by A.N 1 in Science & Mathematics Physics

8 answers

u can understand it very easily . suppose there are any two charged particle (may be psitive or negative or both)and distance between them is 'r' .then the force on each of the charged particle is given by f=k*(q1)*(q2)/(r^2).where k is constant and its value is k=1/(4*pie*E0 )if medium between the particles is vaccum else its value is k=1/(4*pie*E0*Er) where 'Er' is dielectric constant for medium between two particles.'Eo' is permitivity of vaccum. numerical value of k=9*10^9.forces are attractive for unlike cahrges(opposite signs) and repulsive for like charges(same sign)

2006-09-12 20:09:21 · answer #1 · answered by krs 2 · 0 0

Coulomb's Law gives the force between electrical charges. The force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

F = k*{q1*q2)/r^2. If the charges have like sign, the force is repulsive; if the charges have opposite sign, the force is attractive.

If q is in coulombs, and r is in meters, the value of k=1/(4*pi*e0), where e0 is the permittivity of the space between the charges.

2006-09-12 20:03:46 · answer #2 · answered by gp4rts 7 · 0 0

Coulomb's square law states that the force of either attraction or repulsion between any two charges is directly proportional to the product of the charges and inversely proportional to te quare of their distances apart.

2006-09-12 22:07:58 · answer #3 · answered by Nena 1 · 0 0

Basically it says that the force (repulsive or attractive, based on the charge, plus and minus attract, plus and plus repel, minus and minus repel) between two electrically charged objects (assuming having very small radius so that they can be approximated as points) is directly propertional to the product of the magnitude of their individual charges and inversely proportional to the square of the distance between them.

The formula is F = [K*(Q1*Q2)]/(D * D)

where K is a constant of proportionality
Q1 and Q2 is the magnitude of the charge on the 2 points
D is the distance between the 2 points.

2006-09-12 20:12:30 · answer #4 · answered by harsh_bkk 3 · 0 0

There are two Coulombs laws. One in Electrostatics and one in magnetism.

Coulomb's law of electrostatics: The force of attraction/repulsion between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distances between them.
F=q1*q2/(r*r) where q1,q2 are the charges and r is their seperation.

Coulomb's law of magnetism: the force of attraction/repulsion between two magnetic poles is directly proportional to the product of their pole strengths and inversely proportional to the square of the distance between them.

F=m1*m2/(r*r) where m1 and m2 are the pole strengths and r is the seperation of the magnetic poles.

2006-09-12 20:10:20 · answer #5 · answered by Anonymous · 0 0

it really is Gauss's regulation. Flux is the amt of container going through the area. So Gauss says the E container going through the area of an enclosed sphere is an same because the enclosed cost divided by employing the permittivity consistent. If the exterior section contained in the priority is symmetrical (spheres, sq. or oblong bins) then we do not favor calculus = EA=flux. the biggest part of this theorem is that electric powered fields emanate from a element and shuttle isotropically (both in all instructions).

2016-11-26 20:51:54 · answer #6 · answered by Anonymous · 0 0

Charges exert a force on each other (attraction if of opposite sign, repulsion if of the same sign).
Simply, without using scientific notation:

If you have two charges then:
a) doubling the size of one charge will double the force (attraction or repulsion) between them.
b) doubling the distance between them will reduce the force between them to one quarter (1 / 2 squared) of the original value.

2006-09-12 22:06:59 · answer #7 · answered by hippoterry2005 3 · 0 0

i have no time to discuss...my advise is that....research and do all things to understand and answer your question...because you yourself can only answer your question...thank you!

2006-09-12 20:15:32 · answer #8 · answered by "mAaN2j_tRiXiE" 1 · 0 0

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