Slope -2, passing through (-1,5)?

Question

write a formula for a linear function f whose graph satisfies the conditions

Answer 1

(-1,5), m = -2
5 = -2(-1) + b
5 = 2 + b
b = 3

ANS : y = -2x + 3

Answer 2

y=mx+b, where m is the slope and b is a number you solve for. So y = -2x+b Plug in x = -1 and y = 5 into the equation:
5 = (-2)*(-1)+b
5 = 2+b Now subtract 2 from both sides:
3 = b

Now you know the formula: y = -2x+3

Answer 3

Formula for point slope form is:

y-y1=m(x-x1)

Where (x1,y1)=the point where it passes
m=slope

substitute:

y-5=-2(x-(-1))
y-5=-2(x+1)
y=-2x-2+5

y=-2x+3; This is a slope-intercept form. If you need the general form, here it is:

2x+y-3=0

Answer 4

let eqn is y= mx + c where m is the slope and c is the y-intercepr
here m= -2
then y= -2x+c
as it passes through (-1,5)
so 5=-2*(-1)+c
or, c=5-2=3
eqn is y=-2x+3
or, 2x+y=3

Answer 5

to locate the slop you subtract Y2 it extremely is -5 from Y1 it extremely is 15 and divide it via X2 it extremely is -8 minus X1 it extremely is -2 so (-5) - 15 = -20 and (-8) - (-2) = -6 so which you get -20/-6 which fits to constructive 20/6 and decreases to 10/3! your answer is D!

Answer 6

the linear equation is y=mx+c,

wh know that m= -2 , thus,

y=-2x+c-------- (1) , if we substitute x=-1 and y=5 in equation 1.

we get, c= 3. so that we get, y= -2x+3

Answer 7

y = -2x + 3 (slope intercept form) or 2x - y = -3 (standard form)

Answer 8

y = mx +b
y = -2x + b
5 = -2*(-1) + b
b = 3
y = -2x + 3


Doug