Acceleration of a Rocket Ship?

Question

If a rocket ship reaches 82 meters in 3.6 seconds, what is the magnitude and direction of the rocket's acceleration? What is its speed at this time?

Answer 1

The speed of the rocket
= the distance travelled by the rocket/time
= 82 m/ 3.6 s
= 22.7778 m/s

The acceleration of the rocket
= (the final speed - the initial speed) /time
= (22.7778 m/s - 0 m/s)/time
= 6.3271 m/s^2

The direction of the rocket's acceleration is not given. But we can assume that the rocket accelerating upward.

Answer 2

Since v = at then a = v/t = 83/3.6 = 23.055 m/s²

Sinve v = v0 + at²/2 and v0 is zero,
v = 23.055*3.6²/2 = 149.39 m/s

Can't say much about the direction since no information about it is given.


Doug