explain how to determine the volume of a glass marble?

Answer 1

Use a graduated cyclinder...measure water volume accurately, add marble and measure new water level.

Answer 2

volume of a sphere :
V = [(4/3) x Pi x r³]

To get the radius, find the diameter and divide by 2.

You can get the diameter 2 easy ways:
1. use a caliper.
2. put the marble on a table, use a level (the thing you use to hang pictures), hold the marble in place with the level, with a ruler measure the distance between the table and the level.

Those above two methods will give you the same number, which is the diameter. Now divide it by 2 to get the radius & plunk it into the formula.


You can also displace water, if you trust the accuracy of your equipment. A marble is quite small and doesn't displace a lot of water, so your readings can easily be off.

If you do a water displacement test, you can then take the answer you got there (volume), put it in the equation and determine what the radius of the sphere is. Now double that radius & it should be equal to the diameter you got in the top 2 methods.
Your displacement volume, use in the equation should give you the same diameter that was obtained by the above 2 methods

Best answer?

Answer 3

When dealing with a round object, the best way to determine it's volume is by measuring the amount of water it will displace.

Use something you can accurately measure water with, such as a 10mL graduated cylinder. Fill it up to a certain level (5mL should be plenty for a marble). Then drop the marble into the water, and measure what the new level is. Subtract the original level from the new one, and you have your volume.

Just as a side note, 1mL = 1cm^3, so the units work out fine in that regard, since we're taught to think of volume in cubic units.

Answer 4

There are two ways. One is measuring the amount of water the marble displaces. The other way is to first determine the radius (half the diameter) of the marble. Then using r as the radius, use the formula V = 4/3 pi r^3.

Answer 5

You could do the experiment where Aristotle (I think it was him, if not, it was an Ancient Greek) discovered that you can measure the volume of an object by submersing it in a liquid. The volume of the object will be the change in the liquid level. Marbles sink in water, put some water in a measuring cup/cylinder, record the level, put the marble in, record the new level, and there you go!

Remember that 1 mL = 1 cubic cm.

Answer 6

Put some water in a measuring cylinder. Drop the marble in it. The difference in volume is the volume of the marble.

Answer 7

if ya wanna know the volume of something like that you need to fill a graduated cylinder with water to an even marking, lets say 100 mL. you then gently drop the marble into the cylinder and see how much the water raises. THats your volume. So if it started at say 100 and then was at 122 mL after the marble then your volume is 22 mL

Answer 8

All of the answers are good if you're looking for the DISPLACEMENT of the marble. If you want the volume INSIDE the marble, use this formula: volume=4/3¶r cubed
volume is 3 X pi (3.14) X the radius of the sphere cubed, divided by 4
lets say the radius of the sphere is 2 cm.
2 cubed(2x2x2)=8
8x3.14=25.12
25.12x3=75.36
75.36 divided by 4=18.84 CUBIC INCHES, or 18.84 INCHES CUBED

Answer 9

have you ever observed this result? this is rather unwise to think of issues you haven't any longer observed. The downward tension on a physique is the sum of gravitation, buoyancy, and air resistance. If the balls are of equivalent length the buoyancy could be equivalent. Air resistance relies upon on length, shape, and floor smoothness, which will or won't be the comparable for the two bodies. in spite of everything, the forces on the two bodies do no longer be certain to proportional quantities, so the denser lead falls quicker than the glass in maximum tests. yet another occasion of the magnitude of observations: this is been observed that raindrops of any length fall at a relentless velocity, approximately 10 ft in line with 2nd. this is by using the fact larger raindrops flatten extra, increasing air resistance.

Answer 10

you must use this formula

http://upload.wikimedia.org/math/b/5/9/b59ac5ca15c38bc95983f1f0abc68f4c.png

all you need is the radius (meassure the diameter and divide by 2)