The width is 7/10 of the length of the rectangle and the perimeter is 68...what is the width
2006-09-12 14:21:41 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
solve for w
2 ( w + 10/7 w ) = 68
2006-09-12 14:25:26 · answer #1 · answered by oracle 5 · 0⤊ 0⤋
let length = x
therefore, width = 7x / 10
perimeter of rectangle = 2 ( length + width)
there fore 68 = 2 ( 7x/10 + x)
68= 17x/5
x= 5 * 68 / 17 (* is the sign for multiplication)
x= 20
width = 7/10 of 20
= 14 answer
2006-09-12 21:29:11 · answer #2 · answered by shant_p 2 · 0⤊ 0⤋
Let the length be L. Then the width is 0.7 L. Draw a rectangle; label all 4 sides with these terms. Then add them up and make it = to 68
2006-09-12 21:27:06 · answer #3 · answered by hayharbr 7 · 0⤊ 0⤋
width 14 length 20
2006-09-12 21:25:27 · answer #4 · answered by Milton F 1 · 1⤊ 0⤋
perimeter of a rectangle =2(l+w)
P=2(l+w)
P=68 and w=7/10xl now substitute these given values into the general equation
68=2(l+0.7l)
68/2=1.7l
34=1.7l
l=34/1.7=20
2006-09-12 21:31:12 · answer #5 · answered by KAT 2 · 0⤊ 0⤋
w = (7 / 10) * l => l = (10 / 7) * w
68 = 2*w + 2*l
Substitute the first equation into the second one and solve for w. You should end up with w=14 and l=20.
2006-09-12 21:29:14 · answer #6 · answered by achtung_baby 2 · 0⤊ 0⤋
P = 2(L + W)
W = (7/10)L
68 = 2(L + (7/10)L)
34 = L + (7/10)L
340 = 10L + 7L
340 = 17L
L = 20
W = (7/10)(20)
W = 140/10
W = 14
Length = 20
Width = 14
ANS : 14
2006-09-12 23:48:11 · answer #7 · answered by Sherman81 6 · 0⤊ 0⤋