I would be very impressed by anyone who can solve this problem -_-.
2006-09-12 14:08:51 · 5 answers · asked by Yao Ming 2 in Science & Mathematics ➔ Mathematics
If x^4-1/x^4 = 1, then
x^4 - 1 = x^4
Subtracting x^4 from both sides gives
-1 = 0
There is no solution.
Cute. I'm impressed.
If x = 1, then 1-1/1 =1
Ooops! 1-1 is 0! 0/1 =0!
2006-09-12 14:18:08 · answer #1 · answered by F. Frederick Skitty 7 · 0⤊ 1⤋
1
2006-09-12 21:11:38 · answer #2 · answered by lonesomewalks 3 · 0⤊ 0⤋
(x^4 - 1)/(x^4) = 1
x^4 - 1 = x^4
0x^4 = 1
x^4 = undefined
so
(x^64 - 1)/(x^64) cannot be solved, unless you meant
x^4 - (1/(x^4)) = 1
(x^8 - 1)/(x^4) = 1
x^8 - 1 = x^4
x^8 - x^4 - 1 = 0
(x^4 - 1)(x^4 + 1)
(x^2 - 1)(x^2 + 1)(x^4 + 1)
(x - 1)(x + 1)(x^2 + 1)(x^4 + 1)
The only real numbers are x = 1 or -1
1 - (1/1) = 1 - 1 = 0
(-1)^64 - (1/((-1)^64)) = 1 - (1/1) = 1 - 1 = 0
ANS : 0
2006-09-13 00:26:39 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
answer is 1
2006-09-13 02:38:46 · answer #4 · answered by free aung san su kyi forthwith 2 · 0⤊ 0⤋
1 !!! it is just the same with the first the numeric value is just changed
2006-09-12 21:16:36 · answer #5 · answered by Anonymous · 0⤊ 0⤋