exerted equal horizontal force of 549N in order to keep the basket moving at a constant vlocity of 1.25 m/s.
how much work was done by friction?? (answer in Kj)
2006-09-12 14:00:52 · 3 answers · asked by cas0086 1 in Science & Mathematics ➔ Physics
Given two facts:
1. work = force * distance
2. 1 joule = 1 Newton meter
You compute the amount of work as:
549 N * 2 villians * 7.57 m = 8311.86 J
or 8.312 KJ.
I'm assuming that you mean the villians each exerted 549N. If they exerted a total of 549N together, then you need to divide the answer above by two (remove the "* 2 villians" term). The speed (1.25 m/s) is irrelevant.
2006-09-13 09:37:51 · answer #1 · answered by ChicagoDude 3 · 0⤊ 0⤋
Work equals force times distance. The speed does not matter at all, except for the fact that it is constant so you can ignore acceleration.
2006-09-12 21:08:39 · answer #2 · answered by campbelp2002 7 · 0⤊ 0⤋
Need to know if the warehouse floor was cover with a thick mass of ice.
2006-09-13 12:14:01 · answer #3 · answered by donutmiddel 3 · 0⤊ 0⤋