ah am too late; ok lets get started;
ax+b=cx+d
ax-cx = d - b;
Factor x
x(a - c) = d -b
x = ( d -b ) / (a - c)
Thats all.
Good Luck.
2006-09-12 10:44:29
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answer #1
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answered by sweetie 5
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Question:
|ax+b| = cx + d
how to show sometimes the above has 2 roots, sometimes 1 root and sometimes no roots. Hopelessly lost on how to start...
so far I have
1. ax+b = cx+d
2. -ax-b = cx+d
using 1.
x = (d-b)/(a-c)
using 2.
x= -(d+b)/(a-c)
I think your teacher is looking for values of a, b, c and that will give 1 root, 2 roots or no roots.
For example if a = 1, d = 1 and b = c = 0 then the equation becomes
|x| = 1
In this situation x can be 1 or -1 and thus this is a situation with 2 roots.
Can you find choices for a, b, c and that will give no roots? 1 root?
Penny
2006-09-12 16:54:09
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answer #2
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answered by babai_ib 3
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The idea is to group all the x terms together on one side and all the non-x terms on the other. Then divide as necessary to get to just x.
Original equation:
ax + b = cx + d
Start by subtracting cx from both sides:
ax - cx + b = d
Now subtract b from both sides:
ax - cx = d - b
Now factor out a common x term:
(a - c)x = d - b
Now divide both sides by a - c:
x = (d - b) / (a - c)
2006-09-12 16:51:51
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answer #3
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answered by Puzzling 7
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ax + b = cx + d
ax - cx + b = d (subtracted cx from both sides. (Put all the xs on one side of the equation))
ax - cx = d - b (subtracted all constants from the x side.)
(a - c) x = d - b (factored out the x.)
x = (d-b) / (a-c)
Solving for x just means getting all the other garbage on the other side of the equals sign from x.
2006-09-12 16:49:52
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answer #4
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answered by J G 4
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putting like terms together the equation becomes:
ax-cx=b+d
Taking the common factor x out on the right side of the equation we have:
x(a-c)=b+d
Dividing both sides by a-c will give you the value of x
x(a-c)/(a-c)=(b+d)/(a-c)
x=(b+d)/a-c
2006-09-12 16:54:31
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answer #5
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answered by monktash 1
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A visual of the step by step instructions on solving for a letter:
http://regentsprep.org/Regents/Math/formulas/litless.htm
2006-09-12 16:50:41
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answer #6
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answered by ME! 3
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ax-cx = d - b;
Factor x
x(a - c) = d -b
x = ( d -b ) / (a - c)
2006-09-12 18:11:13
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answer #7
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answered by Amar Soni 7
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ax+b=cx+d
(a-c)x=d-b
x=(d-b)/(a-c)
2006-09-12 16:48:50
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answer #8
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answered by curious 4
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x = (d-b)/(a-c)
2006-09-12 16:48:07
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answer #9
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answered by metatron 4
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