ah am too late, i wont have chance to get top answer, but i dont give up.
It's our inequality
3q+11+8q>99
3q+8q > 99 - 11
11 q > 88
q > (88/11)
q> 8
the correct answer is Part D ; q>8
Thats all.
Good Luck.
2006-09-12 10:39:09
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answer #1
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answered by sweetie 5
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Let's do it in steps.
3q+11+8q>99
11q + 11 > 99 (combine 8q and 3q)
11q > 88 (subtract 11)
q > 8 (divide by +11. If we divided by a negative we'd need to change the sign)
I hope this helped you understand the concept as well as the answer to this particular problem. Send on another if it didn't!
2006-09-12 09:40:42
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answer #2
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answered by J G 4
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Just do it like a normal equation. You only have to watch out if you are multiplying by a negative number, then you'd need to switch the direction of the inequality.
Original equation:
3q + 11 + 8q > 99
Group like terms:
11q + 11 > 99
Subtract 11 from both sides:
11q > 88
Divide by 11 (which is positive, so no change to the inequality):
q > 8
It's also a good idea to try a couple numbers at the boundary (7.9, 8.0, 8.0) to see if the inequality is correct:
7.9 and 8.0 shouldn't satisfy the equation, but 8.1 will.
D. q > 8
2006-09-12 09:39:27
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answer #3
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answered by Puzzling 7
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3q+8q +11>99
11q+11>99
11q>88
q>8
Hence correct answer is D
2006-09-12 09:52:48
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answer #4
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answered by curious 4
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D. q>8
subtract 11 from both sides. Then 11q>88 then divide 11 on both sides.
2006-09-12 09:42:21
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answer #5
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answered by July 1
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The answer is q>8 (answer D)
2006-09-12 09:41:49
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answer #6
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answered by Anonymous
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