A chemist pours sodium chloride, or table salt, into a beaker. If the beaker plus the sodium chloride have a mess of 84.8 grams, and the beaker itself has a mass of 63.3 grams, what is the mass of the sodium chloride that was poured into the beaker?
2006-09-12 09:35:18 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
84.8
-63.3
_____
21.5 is the answer.
2006-09-12 09:37:56 · answer #1 · answered by Administrator 2 · 1⤊ 1⤋
This is a subtraction problem.
The beaker + the chloride substance = (beaker+ substance)
63.3 + ? = 84.8
Subtract 63.3 from 84.8 to get your answer! Good luck!
2006-09-12 16:38:33 · answer #2 · answered by J G 4 · 0⤊ 0⤋
Yo, Da Man, can't handle simple subtraction?
beaker plus salt = 84.8 grams
beaker = 63.3 grams
84.8 - 63.3 = 21.5 grams salt
2006-09-12 16:37:59 · answer #3 · answered by Dave_Stark 7 · 0⤊ 0⤋
Always realize what the problem is asking you to do: basically in this problem you're subtracting 84.8-63.3=21.5
If you need anymore help email me please!
2006-09-12 16:43:23 · answer #4 · answered by Deltadiva 2 · 0⤊ 0⤋
Just subtract. The difference is the NaCl
2006-09-12 16:37:29 · answer #5 · answered by davidosterberg1 6 · 1⤊ 0⤋
84.8 - 63.3
2006-09-12 16:40:34 · answer #6 · answered by Gabrielle 6 · 0⤊ 0⤋