you type well for a second grader... I'm skeptical (and if you know what that means, you're noat a second grader)
Word problems are the most important thing to learn in math... This is a subtraction problem... Instead of finding out how many more laps Megan swam, think of it as how many less laps Melody swam.....
16 laps
- 9 laps
________
7 laps
2006-09-12 08:35:44
·
answer #1
·
answered by In the light 3
·
1⤊
0⤋
7
2006-09-12 15:37:19
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
7
2006-09-12 15:36:19
·
answer #3
·
answered by IthinkFramptonisstillahottie 6
·
0⤊
0⤋
There is most likely a calculator on your computer to help you with this.
If Megan swam 16 laps: 16
and Melody swam 9 laps: 9
then how many more pas did Megan swim than Melody?
16-9=__
It might help if you lay out 16 coins. Take 9 of them away. How many coins are left? (Count them) That is the answer.
It's important to know you're subtraction, so I won't just tell you the answer. :)
2006-09-12 15:39:56
·
answer #4
·
answered by Anonymous
·
1⤊
0⤋
megan = 16 laps
melody = 9 laps
as you know, swimming 16 laps is more than swimming 9 laps, so you have to find the difference between 16 and 9 to find out 'how many more laps megan swam.' so you subtract 9 laps from 16 laps which would be:
16 laps
- 9 laps
------------
7 laps...is your answer.
count on your fingers starting from 10 until you get to 16 and see how many fingers you are holding up.
ur in second grade?? maybe you should ask your teacher for help and teach her how to type.
2006-09-12 15:41:11
·
answer #5
·
answered by dontkno 2
·
0⤊
0⤋
the correct answer is not 5 but 7. You can figure this out by subtracting 9 from 16. It is... how many numbers are between 9 and 16. That is your answer.
2006-09-12 15:38:52
·
answer #6
·
answered by sha scrilla 3
·
0⤊
0⤋
Wow, you have excellent typing skills for a second grader.
16 is 7 more than 9. So your answer is 7.
16
- 9
-------
7
2006-09-12 15:47:45
·
answer #7
·
answered by Lyrical Goddess 4
·
0⤊
0⤋
7 more laps
2006-09-12 15:40:06
·
answer #8
·
answered by hoppo 2
·
0⤊
0⤋