English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

A student used 20 ml water instead on 30 ml for extraction of salt from mixture. How would this change effect on the percentage on NaCL...?

2006-09-12 08:12:23 · 4 answers · asked by hetrp 1 in Science & Mathematics Chemistry

4 answers

If you reduce the amount of solvant by 1/3 you have increased the percentage of NaCl by 50%.

Think of it this way. Assume that you dissolved the salt in 30ml of water. Then divide the water into two containers, one with 20 ml and the other with 10 ml.

Now the amont of salt in the 10 ml is going to be 50% of the amount dissolved in the 20 ml. So if you were to remove that salt from the 10ml and put it in the 20 ml container, you will increase the percentage of salt by 50%.

2006-09-12 08:38:57 · answer #1 · answered by Alan Turing 5 · 1 1

It depends on the amount of NaCl. 20 ml will dissolve so much. 30 ml will dissolve more than 20 ml. If the amount that is in the mixture is at or less than the amount 20 ml will dissolve, then no problemo. But I would do it all over w/ 30ml. since the unknown would be the NaCl in the mixture.

2006-09-12 15:20:19 · answer #2 · answered by tjc 2 · 1 0

Only 2/3 of NaCl will dissolve

2006-09-12 15:28:24 · answer #3 · answered by Amar Soni 7 · 0 1

there is a limit to how much NaCl can be dissolved in water (saturation point) so some salt could have been left behind. that's why you do several washings.

2006-09-12 15:24:39 · answer #4 · answered by shiara_blade 6 · 0 1

fedest.com, questions and answers