2006-09-12 06:39:56 · 6 answers · asked by pnoiz1 2 in Science & Mathematics ➔ Mathematics
(5i)^3 = 5^3 * i^3 = 125(-i) = -125 i
Then :
By coefficients comparison :
a=0
b=-125
2006-09-12 06:44:05 · answer #1 · answered by jmdanial 4 · 1⤊ 0⤋
in general, you can express 5i as 5(cos90 + i sin 90)
using the theorem, (5i)^3 = 5^3(cos270+i sin270) = -5i, meaning that there is no real part in the solution
you can do this problem simply as: (5i)^3 = 5^3 * i^3 = 5^3 * -i = -125i
2006-09-12 13:46:42 · answer #2 · answered by m s 3 · 1⤊ 0⤋
(5i)^3 = -125i
a+bi form is: 0-125i
2006-09-12 15:29:20 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋
a=0 and b=-125
so 0+(-125)i
2006-09-12 13:51:16 · answer #4 · answered by raj 7 · 1⤊ 0⤋
In your book
2006-09-12 13:41:17 · answer #5 · answered by Anonymous · 0⤊ 1⤋
First, you have to re-route your binomials in order to properly defernilate the cirramulus. Duh.
2006-09-12 13:43:27 · answer #6 · answered by Anonymous · 0⤊ 1⤋