in what time could either have done it alone.
this chapter comes under applications.
2006-09-12 06:10:58 · 3 answers · asked by sweety madhu 1 in Education & Reference ➔ Homework Help
OK.
A did 4/5 of the work in 20 days. 20 * 5/4 = 25 days for A to complete it alone.
1/5 of the work was done in 2 days by A and B. In 2 days, A can complete 2/25's of the work (2 days/25 total days). B therefore did 3/25's of the work in 2 days.
B therefore could have completed the work in 2 * 25/3 = 50/3 days = 16 days, 16 hours.
2006-09-12 06:14:52 · answer #1 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋
25 days. 20 is 4/5 of 25.
5 10 15 20 25
2006-09-12 06:13:50 · answer #2 · answered by cab veteran 5 · 0⤊ 0⤋
A and B's one day's work=5/22
A's one day's work=4/100
A could have done it alone in 25 days
B's one day's work=1/22-4/100
=100-88/2200=12/2200
so B alone could have done it in=18.3 days
2006-09-12 06:25:24 · answer #3 · answered by raj 7 · 0⤊ 0⤋