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yes...when they are equally inclined on a plane......that is each has an angle 120 degree with the other.....then the two of the vectors will hav a resultant which is opposite to the third vector.....then th net result is zero

2006-09-12 05:12:26 · answer #1 · answered by friend 3 · 1 0

Yes. Assuming a R^n vector space then only if n > 1

Example in 2 space

(1,0), (-sqrt(3)/2,1/2) ,(-sqrt(3)/2,-1/2)

They all have magnitude 1

Note that if you want 'm' vectors to add to zero a simple way is to take the 'n sphere' and distribute the m vectors evenly around that. In the 2 dimensional case take the 2-sphere (i.e., circle) and distribute them evenly around it. This gives 120 degrees between each.

2006-09-12 05:18:18 · answer #2 · answered by Anonymous · 1 0

Yes, the proof rests on the triangle of vectors which can be found in any standard text.

2006-09-12 06:03:41 · answer #3 · answered by ag_iitkgp 7 · 0 0

a million. "previous guy" off of ZZ good's First Album 2. "Brown Sugar" off of ZZ good's First Album 3. "basically have been given Paid" off of Rio Grande airborne dirt and dust Gotta keep it previous college for the actual ZZ good

2016-11-07 04:20:41 · answer #4 · answered by Anonymous · 0 0

You get the anti-gravity eureka. This is what Egyptians mastered. thanks.

2006-09-12 05:31:30 · answer #5 · answered by Anonymous · 0 0

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