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an equal but opposite force on you. Will it possible for you to accelerate the object in view in these equal and opposite forces.

2006-09-12 03:37:35 · 7 answers · asked by cristina c 1 in Science & Mathematics Earth Sciences & Geology

7 answers

A good question. Try to understand the Newton's law properly.

The forces due to action and reaction do not act on the same body. Hence, acceleration is possible.

Mail me for more details.
Good luck
RAVI

2006-09-12 03:41:55 · answer #1 · answered by sravi_iyer 1 · 2 1

Ravi is correct.

If you hit a ball, you exert some force on the ball and the ball exerts the same force on you. Since you're heavier than the ball and since a=F/m, the ball accelerates more than you do.

When you jump, you actually exert a force on the Earth. But now the Earth is much heavier than you are so you accelerate more.

The most illustrative example may be too skaters, standing in front of each other and pushing. They will now both be accelerated, in opposite directions.

You may notice that the two-skater-system consisting of both skaters as one object will not get accelerated. Their common center of mass does not move.

So indeed, you can't accelerate yourself by pulling yourself by your hair or kicking your own but, since the force exerted on your but will be neutralized by an equal and opposite force on your foot. But by exerting the force on some other object, you can accelerate yourself.

2006-09-12 04:13:55 · answer #2 · answered by helene_thygesen 4 · 1 1

It depends on the mass of the object relative to your mass. If you push a soccer ball it will accelerate. If you push a battleship it will not accelerate.

JMB

2006-09-12 03:49:28 · answer #3 · answered by levyrat 4 · 0 1

Yes.

2006-09-19 16:48:31 · answer #4 · answered by spongeworthy_us 6 · 0 0

Obviously it is. Otherwise you couldn't have moved your fingers to type this dumb question.

2006-09-12 03:41:02 · answer #5 · answered by icetender 3 · 0 2

What?

2006-09-12 03:39:52 · answer #6 · answered by KittyK 2 · 0 2

Im lost......

2006-09-19 13:41:12 · answer #7 · answered by ItsMeTrev 4 · 0 0

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