How do I prepare of HCl 37%, HCl 2% & HCl 1molar?

Answer 1

Actually HCl is a gas and what you buy from suppliers is concentrated HCl around 37%
You should see on the label the exact concentration (maybe 37.3%) but lets say it is 37%.
Therefore the first solution you don't make it; you buy it.

Let's assume you want to prepare Vfinal ml of each solution
Then you will need Vstock ml from the 37%

You can use the formula M1*V1=M2*V2 even in the % case because we are talking about the same compound so the factors by which you have to multiply/divide the % to convert to molarity are simplified;

so for 2% => 37 * Vstock = 2* Vfinal
thus Vstock =(2/37) * Vfinal ml
So you take a suitable volumetric cylinder or flask, put a bit of distilled water, add Vstock ml of the 37% solution, fill-up to Vfinal with distilled water and mix.

For 1 molar we need to do the conversion
37% is 37 gr/ 100ml or 370 gr/ liter or 370/MW mole/lt =370/38.5= 9.61 M

So 9.61 *Vstock= 1* Vfinal
=> Vstock =(1/9.61)* Vfinal ml.

Answer 2

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RE:
How do I prepare of HCl 37%, HCl 2% & HCl 1molar?

Answer 3

Hydrochloric Acid 37

Answer 4

To ansewr this question we must know the " Acide(HCl) degree of purification" but now we assume it HCl 100%. so
to preaper HCl 1molar:
1mol HCl = 1+35.5 = 36.5 g
Dencity = 1.84 (for HCl)
so the Volume of Acide is:
V=m/D = 36.5 / 1.84 = 19.38 cc

so if you mix 19.8 cc HCl (100%) + 80.2 cc Water you will preaper HCl 1 molar.

HCl 37% means 37 cc HCl in 100 cc Water.
and HCl 2% = 2cc HCl + 98 cc Water.

we can also calculate this from N1V1=N2V2 furmula.

Answer 5

2% is consider to 100 that said 0.02 and it is multiply amount water required in ml