Pete wentz-Total hotty!
Ryan Ross-so cute!
Jesse Mcartney-umm hes ok
Tyson Ritter-Hmmm has good music
2006-09-12 01:27:06 · 13 answers · asked by Anonymous in Entertainment & Music ➔ Celebrities
Pete Wentz is okay..but you do know he's gay right??
Who's Ryan Ross.
Jesse McCartney is ok.
Tyson Ritter-whose that??
2006-09-12 10:33:35 · answer #1 · answered by C M 3 · 0⤊ 1⤋
Pete Wentz - Umm.. too short & dresses funny .. sorry lol .. I like F.O.B. tho
Ryan Ross - He's pretty cute .. & so is Brendon
Jesse McCartney - Ew .. I think he's ugly
Tyson Ritter - Sooo hott!!!
2006-09-12 19:25:06 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I never heard of them except for Jesse mcartney and he isnt really that cute lookin
2006-09-12 10:13:02 · answer #3 · answered by *<i:o) 4 · 0⤊ 0⤋
Pete - Heck Yeah
Ryan - Yup
Jesse Mcarthney - Sure
Tyson - Gotta love his eyes
2006-09-12 08:33:17 · answer #4 · answered by tre_wingo 3 · 0⤊ 0⤋
pete-not so much, and don't like his band either, sorry.
ryan-eh
jesse-little boy, could pass for a carter
tyson- good eyes
p.s. i had to look up pictures of all but mccartney. i had heard of all but ritter, but never looked at them.
2006-09-12 09:43:12 · answer #5 · answered by bored_ass_little_girl 5 · 0⤊ 0⤋
Sorry, i only know Jesse Mcartney - he's yummy
2006-09-12 09:37:01 · answer #6 · answered by Desert Rose 2 · 0⤊ 0⤋
Oh my god, I just know who is Jesse Mcartney. (I think)
Is he the one who act the hot gardener in desparate housewife?
If he is, then he's not cute, but he's hot.
2006-09-12 09:52:08 · answer #7 · answered by Notorious Guy 6 · 0⤊ 0⤋
Never heard of them. Are they a barbershop quartet?
2006-09-12 08:29:19 · answer #8 · answered by J D 5 · 1⤊ 1⤋
hy hons gay partners tevie and davey hons emmm yes!1 we love pete too hons, and ryaan owe yes yes ys!! the rest bleh!! yur two choices yes hond deffintelly emmm!! us gay partners love emm hons!!
2006-09-12 08:31:20 · answer #9 · answered by Anonymous · 0⤊ 1⤋
Never heard of any of them....sorry!!
2006-09-12 08:51:52 · answer #10 · answered by firefly 4 · 0⤊ 0⤋