It's rho*gh, where rho is the fluid density, g is the acceleration of gravity, and h is the fluid height. Water has a density of 1 g/cm^3, which is 10^-9 kg/m^3, and the acceleration of gravity is 9.8 m/s^2. So you end up with 9.8h x 10^-9, with h in meters.
2006-09-12 01:27:34
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answer #1
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answered by DavidK93 7
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P(pressure)=h(depth of water coloumn) x d(density of water/liquid) x g(accleration due to gravity)
P.S.-This formula is applicable for all liquid pressure
Regards-
The $c@recrow
2006-09-12 08:32:40
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answer #2
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answered by SkkARd 3
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liquid pressure = height x density x force of gravity
since density of water is 1 then water pressure = height x 9.8
2006-09-12 08:56:07
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answer #3
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answered by dwarf 3
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P=(D*V*9.8)/A
where d is density, v is volume and a is the area of the lower surface of water. this is the pressure exerted by water on the bottom surface.
2006-09-12 08:26:14
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answer #4
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answered by ankit pruthi 2
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Hmm,if i'm not wrong,it was ;
(density of the liquid x height of the liquid column) / surface area
2006-09-12 08:25:19
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answer #5
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answered by Leprechaun 6
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height in inches/feet x by .434 gives you pounds per sq inch.
2006-09-12 08:24:10
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answer #6
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answered by John E 3
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