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It needs to be in language suitable to be understood by a 14 year old.

2006-09-12 00:29:16 · 4 answers · asked by Queen Cate, The Gorgeous 2 in Science & Mathematics Earth Sciences & Geology

4 answers

It's not really a cycle, since rocks can change from one to the other, not necesarily in a specific order, but subject to different regimes of temperature and pressure.

You start out with a volcanic rock at the surface, such as granite, basalt, etc. This rock is broken down by erosion into sediment particles (sand or clay sized to boulder sized). These particles are buried, compacted and cemented at low temperatures and pressures forming sedimentary rocks. These rocks, if they are buried even more and are subjected to higher temperatures and pressures, they become metamorphic rocks. Both sedimentary and metamorphic rocks can be transported into a subduction zone where they melt (even higher temperatures and pressures), form magma and are then cooled into volcanic rocks again.

2006-09-12 03:54:20 · answer #1 · answered by Jenni77 2 · 0 0

The cycle is as follows........

Wash...Rinse...Dry...

I'm sorry QueenCate but that since it is 4:45AM California time I thought maybe a little humor might help. I can't seem to get to sleep and I haven't any idea what time zone you might be in.

On the serious side let me give it a shot.

The rock cycle describes one of the most fundamental concepts in geology; the transition through geological time among the 3 main rock types. Those types; in order, are sedimentary, metamorphic and igneous. This transitional movement through geological time is known simply as "that rocks are always on the move:.

This theory is attributed to the 18th century father of Geology; James Hutton.

2006-09-12 00:54:34 · answer #2 · answered by iraq51 7 · 0 0

ok,first you learn to play a guitar,then go to rehab,thats the cycle of rock

2006-09-12 01:43:51 · answer #3 · answered by john doe 5 · 0 0

Well, I think this article could have been written just for you :)

2006-09-12 00:36:24 · answer #4 · answered by Anonymous · 0 0

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