2006-09-09 15:52:15 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
3x^2 = 5/9
Divide both sides by 3
x^2 = (5/9)/3
x^2 = 5/27
Take the square root of both sides
x = +/- sqrt(5/27)
Simplify by rationalizing the denominator.
sqrt(5/27) = sqrt(5)/sqrt(27)
= sqrt(5)/sqrt(9*3)
= sqrt(5)/(3sqrt(3))
Multiply the top and bottom by sqrt(3)
= sqrt(5)*sqrt(3)/[3sqrt(3)*sqrt(3)]
= sqrt(15)/[3*3]
= sqrt(15)/9
Answer: sqrt(15)/9 or -sqrt(15)/9
2006-09-09 16:20:26 · answer #1 · answered by MsMath 7 · 1⤊ 2⤋
3x2 ? That's not a term. That's impossible. Do you mean 3x+2 or -2 or something like that? And it's not multiplication it's algebra. Without a possible equation the answer cannot be given.
2006-09-09 22:57:04 · answer #2 · answered by millancad 5 · 1⤊ 0⤋
Do you mean
3x²=5/9 then
x² = 5/27 (Dividing by 3 both sides)
x = (â5/27)
x = ±( 2.236 / 5.196)
x= ± (0.43033)
substiruting the value of x = +0.43033 or - 0.43033
in 3x² we get
=3 * (0.43033)²
=0.5555555
which is equal to 5/9 = 0.55555
2006-09-10 22:49:41 · answer #3 · answered by Venkatesh V S 5 · 0⤊ 0⤋
Some posters solved for x - is this what you're looking for?
2006-09-10 14:43:23 · answer #4 · answered by Anonymous · 0⤊ 0⤋
andrew do you ride the short bus to school?
2006-09-09 23:19:20 · answer #5 · answered by musicdude909 2 · 0⤊ 1⤋