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You have an 1800 watt hair dryer used for an average of 10 minutes per day at 9 cents Your utility company charges 9 cents per kilowatt-hour of energy. How much does it cost to run the hair dryer each day? each Year?

2006-09-09 14:28:36 · 8 answers · asked by spirit filled 1 in Science & Mathematics Mathematics

8 answers

1800 watts = 1.8 Kilowatts
10 minutes = 1/6 hour
9 ¢ = $0.09
1 year = 365 days

1.8 Kw X 1/6 h X $0.09 = $0.027/day (2.7¢/day)
$0.027/d X 365 d =$9.855/year

(sounds cheap to me, the others are trying you rip you off, they work for the power company.)

2006-09-09 15:17:34 · answer #1 · answered by ? 4 · 2 0

10 minutes is 1/6 of an hour....so each day you use 1800 Watts divided by 1/6 or 300/1000 or 3/10 kilowatt - hour. If you're charged 9 cents per kilowatt hour, your daily cost would be 2.7 cents. 2.7 cents times 365 = $9.85 a year.

And another method:
1800 watts for an hour would be 1.8 kilowatt hours. Every six days you would use 1.8 kilowatt hours. In a year, you use 60.83 times 1.8 or 109.4 kilowatt hours. At 9 cents per, that is $9.85 a year.

Either way, that's a pretty good bargain, don't you think?

2006-09-09 15:00:39 · answer #2 · answered by LeAnne 7 · 1 0

9 min/day x 365 days/year = minutes per year

minutes per year / minutes per hour (60) = hours per year

1800 watts / 1000 = kilowatts (1.8)

1.8 x hours per year = kilowatt hours per year

You should be able to figure it out from here

2006-09-09 14:54:18 · answer #3 · answered by Perry L 5 · 0 1

$0.09 per kilowatt-hour
60 minutes=1 hour
since she used 10 minutes a day, then she used 1 hour in 60 days.
60 days=$0.09

There are 365 days in a year
365days/60 days=6.083 (with 3 repeated)

6.083*$0.09=$54.747=$54.75 per year.

For a day...
$0.09/10=$0.009=$0.01

She spends about 1 cent a day and about 54 dollars and 75 cents a year. If leap year its 54 dollars and 90 cents. =)


Mark as best answer please and thank you. =]

2006-09-09 14:43:34 · answer #4 · answered by >???<Chinita>???< 3 · 1 3

1800 watt = 1.800 kilowatt
10 min per day = 10/60 hr per day = 1/6 h per day

1.800 kilowatt x 1/6 hr per day = .300 kilowatt-hr per day
--- --- --- --- ---
9 cents/kilowatt-hr x .300 kilowatt-hr per day = 2.7 cents per day
2.7 cents per day x 365 days each year = 985.5 cents each year = 985.5/100 dollars each year = $9.85 each year

2006-09-09 15:24:23 · answer #5 · answered by Illusional Self 6 · 2 0

1800 watts = 1.8 kw

1.8 * (10/60) = 1.8 * (1/6) = .3

.3 * 9 = 2.7 cents or $.027 a day

.027 * 365 = $9.855

ANS :
about $0.03 a day
about $9.86 a year

2006-09-09 15:14:49 · answer #6 · answered by Sherman81 6 · 1 1

so, 1800 w=1.8kw

10minutes - 1.8kw
60minutes(1hour) - 1.8kw / 10 x 60
=10.8kw/h

therefore1 year=365 days

10.8kw/h X 365days=3942kw(total use of energy)

cost=3942kw/h X $0.09
=$354.78

the cost is $354.78 per year .

hope that will help u :)

2006-09-09 14:40:01 · answer #7 · answered by Jan 1 · 0 3

$2.16 dollars a day.$788.40 dollars a year

2006-09-09 14:37:37 · answer #8 · answered by muic_dance 2 · 0 3

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