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kim pushes a lawn spreader across a lawn by applying a force of 95N along the handle that makes an angle of 60.0 w/ the horizontal.
a. what are the horizontal and vertical components of the force?
b. The handle is lowered so it makes an angle of 30.0 degrees w/ the horizontal. Now what are the horizontal and vertical components of the force?


Really, i've looked for help in my book/ notes/ internet... i don't get it...

also, does anyone know any sites that can help ppl w/ physics?

2006-09-09 14:26:47 · 3 answers · asked by Sheyna 1 in Science & Mathematics Physics

3 answers

I don't know of any web sites that help with physics, but I do know that your teacher can be very helpful! Ask him/her to help you outside of class. You need to learn how to figure out these problems, you can't just look up the answer in the textbook, because it won't be there. This stuff is only going to get harder, so please get help from your teacher now (it's gotta be face-to-face help, it's nearly impossible to teach physics without drawing diagrams and having live interaction).

To help you along with your problem, draw a diagram of the force, and use trigonometry to decompose the force vector into its x- and y- components.

2006-09-09 14:34:17 · answer #1 · answered by kris 6 · 0 0

Look in your book for a discussion of component, resultant, or vector. What you need to do is resolve the force into horizontal and vertical vectors. That's where you will need the trig that kris talked about.

I am one of 6 or 8 "experts" that volunteer to help in the physics category at allexperts.com. We are qualified. You choose which of us you want to ask and we try to go into more detail than you get here. Try us out:
http://www.allexperts.com/browse.cgi?catLvl=3&catID=1358
But it's still not as good as face to face.

2006-09-09 23:02:03 · answer #2 · answered by sojsail 7 · 0 0

well i would go to help math .com it would help a lot it helped a lot oh and when you search search from google

2006-09-09 21:31:23 · answer #3 · answered by muic_dance 2 · 0 0

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