(5√y)+[√(2y+3)]+[2√(2y^2+3y)]=11-3y
p.s. y^2 means: y × y
y=?
2006-09-09 13:48:30 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(5√y)+[√(2y+3)]+[2√(2y^2+3y)]=11-3y
p.s. y^2 means: y × y
y=?
2006-09-09 13:49:08 · update #1
the first line=11-3y
2006-09-09 13:50:20 · update #2
the first line=11-3y
the first line=11-3y
the first line=11-3y
the first line=11-3y
the first line=11-3y
2006-09-09 15:36:30 · update #3
y=-39/16(+/-)(1/16)*sqrt( (39^2)-32(3-m^2) )
is relation where you get answer:
y=? when your RHS=0=m
otherwise put tentative value of y=1,2,3...and get answers in m.
2006-09-09 14:01:47 · answer #1 · answered by Anonymous · 0⤊ 1⤋
You need to have a result of this equation.
I can only tell you this:
(5ây)+[â(2y+3)]+[2â(2y^2+3y)]=
(5ây)+[â(2y+3)]+[2â(2y+3) (ây)]
Ana
2006-09-09 21:00:50 · answer #2 · answered by MathTutor 6 · 0⤊ 1⤋
You cannot solve for y because you don't have an equation. Also, you cannot simplify the expression. You can rearrange it, but not truly simplify it.
2006-09-09 22:01:12 · answer #3 · answered by Marcella S 5 · 0⤊ 0⤋
i tried it on a graphing calculator and it said the answer was 9.1694795.
2006-09-09 21:06:42 · answer #4 · answered by bmn44 4 · 0⤊ 0⤋
You can't solve for y if you can't tell me what the equation is equal to.
2006-09-09 21:01:44 · answer #5 · answered by TychaBrahe 7 · 0⤊ 1⤋
I'm hungover! Stop harrassing me!
2006-09-09 20:56:25 · answer #6 · answered by Anonymous · 0⤊ 1⤋
i don't know whats more confusing
your question
or
your name :)
you must be a very smart person
2006-09-09 20:49:57 · answer #7 · answered by ? 5 · 0⤊ 1⤋