Write the equation of the line that contains the points (2, 2) and (-3, 12).
Here is part of the answer. Can you identify the missing part?
y = -2x + ___
2006-09-09 10:12:04 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I HATED those math problems that insist on having their line, and not your colinear one. This problem would be so easy to write in point-point form, but NO! It has to be slope-intercept form!
Anyway, if you have most of the equation, put a variable in the empty spot, plug in what you know, and solve! Like this:
y=-2x+b
2=-2*2+b
2=-4+b
6=b
Thus, your equation is y=-2x+6.
2006-09-09 10:21:10 · answer #1 · answered by Mehoo 3 · 0⤊ 0⤋
If you're doing this on a graph, simply find the point at which the line meets the y axis line. So, if your line goes directly over (x=0, y=5) then your answer is y=-2x+5
2006-09-09 17:19:45 · answer #2 · answered by mearsob 2 · 0⤊ 0⤋
Substitute (2,2), get
2 = -2*2 + ___
2 = -4 + ___
What number added to -4 gives you 2? The answer is 6. So you get
y = -2x+6
2006-09-09 17:53:40 · answer #3 · answered by alnitaka 4 · 0⤊ 0⤋
(2,2) and (-3,12)
m = (12 - 2)/(-3 - 2)
m = (10)/(-3 + (-2))
m = 10/(-5)
m = -2
(2,2), m = -2
2 = -2(2) + b
2 = -4 + b
6 = b
y = -2x + 6
ANS : 6
2006-09-09 22:36:31 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
Find the slope:
Slope= y2-y1/x2-x1 = -2
Find the equation:
Y=-2x+6
2006-09-09 17:17:44 · answer #5 · answered by Xeel 1 · 0⤊ 0⤋
assuming the first part is right... then the missing part is 6
2006-09-09 17:23:19 · answer #6 · answered by Anonymous · 0⤊ 0⤋