Which transition in a hydrogen atom would emit the photon of greatest frequency?

Question

n= 12 to n= 6
n = 1 to n = 4
n = 6 to n = 2
n = 35 to n = 2
n = 3 to n= 1
n = 2 to n= 9

which would absorb the photon of the greatest frequency?
n= 12 to n= 6
n = 1 to n= 4
n = 2 to n= 9
n = 35 to n = 2
n = 3 to n = 1
n = 6 to n = 2

Answer 1

The Energy of a photon is given as,
E = hv
where E is the energy, h is Plank's constant, and v is the frequency of the light.
The formula can also be written as,
E = h*c/lambda
where c is the speed of light in the vacuum and lambda is the wavelength of the light.

The energy given off in the form of a photon when a Hydrogen atom's electron jumps down to a lower energy level is given as,
E = b[(1/n_1^2) - (1/n_2^2)]
where E is the energy, n_1 and n_2 are the initial and final principle quantum numbers of the electron, and b is a constant given as,
b = -2 * pi^2 * m_e^2 / h^2
where all these physical constants go into the final, numeric value, of,
b = 2.18 E-18 J

Set the two equations equal to each other and go through you list of possibilities and solve for the frequency of light given off (or absorbed) in each situation.
Yahoo! Answers makes it hard to represent those formulas in a way that is easy to see, they are represented much "prettier" on the web page I reference below (about half way down).

Answer 2

=In your chemistry book