The function is f(x) =kx^3 - 8x^2 - x + 3k + 1 and it has a zero, 2.
How can I find the value of k?
2006-09-09 07:52:22 · 6 answers · asked by kira 2 in Science & Mathematics ➔ Mathematics
Easy... if the zero is 2, then when x is 2 f(x) is 0, so it becomes 8k - 32 - 2 + 3k + 1 = 0 and then 11k = 33, so k is 3.
Any Italian 14 years old guy can solve that.
2006-09-09 07:56:06 · answer #1 · answered by Anonymous · 2⤊ 0⤋
k=3
2006-09-09 07:59:27 · answer #2 · answered by Tejas 2 · 0⤊ 0⤋
Plug in 2: 0= 8k -32 -2 +3k +1
This simplifies to 11k= 33 and therefore k=3
2006-09-09 08:04:08 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋
Substitute x=2 in the equation f(x)=0 and solve for k.
2006-09-09 07:56:44 · answer #4 · answered by A 4 · 0⤊ 0⤋
plug in 2 for x and solve for k.
2006-09-09 09:07:46 · answer #5 · answered by mdavhall1865 2 · 0⤊ 0⤋
Put it on ebay and see if you get any bids
2006-09-09 07:55:14 · answer #6 · answered by luket 1 · 1⤊ 0⤋