x^2 - 2x = t - 2 How to express x in terms of t?

Answer 1

In other words you have to solve the equation for x in terms of t
x^2 - 2x = t - 2
or, x^2-2x+1 = t-2+1, adding 1 on each side
or, (x-1)^2 = t-1
or, x-1 = +-squareroot(t-1)
or, x = +-squareroot(t-1) + 1
So, x = squareroot(t-1) + 1 or x = -squareroot(t-1) + 1

Answer 2

x^2 - 2x = t - 2 How to express x in terms of t
x^2 - 2x + 1= t - 2 +1
x^2 - 2x +1= t - 1
(x-1)^2 = (t-1)
Taking square root both side
(x-1) = plus or minus {Sq root (t-1)}
x = 1 + [plus or minus {Sq root (t-1)}]

Answer 3

x² - 2x = t - 2

x² - 2x + 2 = t - 2 + 2

Adding + 2 to both sides of the equation

x² - 2x + 2 = t

Answer 4

1st Method
First convert it into a form of aX^2 + bX + c =0 , then you can apply the formulae (-b +or- root of b^2 -4ac)/2a = x. Then you will get t in terms of x.
2nd Method
Take t-2 on another side. Accumulate and try to form (x-1)^2 formulae with remaining terms. Take remaining terms to right side again. apply square root and then take -1 on another side you will get x in terms of t.

PS::-- Try to do your homework yourself , after at least 10 tries see the answers.

Answer 5

x^2 - 2x + 1 = t - 1

(x-1)^2 = t - 1

x =(t - 1)^(1/2) + 1

Answer 6

you'd have to factor it

get the t by itself

x^2 - 2x + 2 = t

then factor it to (x-1) (x-1) = t
so if you had to solve it, t = 1

Answer 7

x(x-2) = t - 2
x = (t- 2) / (x - 2)

Im not 100% sure though

Answer 8

add 1 on both sides
x^2-2x+1 = t-1
(x-1)^2 = t-1
x -1 = +/-sqrt(t-1)
x= 1+/- sqrt(t-1)

Answer 9

x=[2 +/- SqRt(4t - 2)] / 2

Or in english: x equals 2 plus or minus the square root of 4t minus 2, all divided by 2.

Answer 10

x(x-2)=t-2 => x=t-2/x-2 i'll answer this question 4 u later right now i'm buse