2006-09-09 02:08:50 · 3 answers · asked by blah blah 1 in Science & Mathematics ➔ Chemistry
Zn + 2HCl -> ZnCl2 + H2
no of moles of Zn used=9.76/(65.4)=0.149235474
Mole ratio: 1 Zn: 1 ZnCl
So no of moles of ZnCl produced=0.149235474
mass of ZnCl produce=0.149235474 x (65.4+ 2(35.5))=20.4g(3sf)
hope this helps..
2006-09-09 05:08:10 · answer #1 · answered by alien 1 · 0⤊ 0⤋
This is a standard kind of stoichiometry question. Use the molar mass of zinc to convert the grams of zinc into moles of zinc. Then convert moles of zinc to moles of zinc chloride (there is a 1:1 relationship in this case). Finally use the molar mass of zinc chloride to calculate the gram of zinc chloride.
So, your calculation will look like this:
9.76 g Zn(1 mol Zn/65.39)(1 mol ZnCl2/1 mol Zn) (136.29 g ZnCl2/mol ZnCl2)=____
2006-09-09 02:17:15 · answer #2 · answered by hcbiochem 7 · 0⤊ 0⤋
Zn + 2HCl = ZnCl2 + H2
(40gm) (40+2*35)gm
(40gm) (110 gm)
40 gm of Zn gives = 110 gm of ZnCl2
9.76 gm of Zn will give=(110/40)x9.76=26.84 gm
2006-09-09 04:05:49 · answer #3 · answered by Amar Soni 7 · 0⤊ 0⤋