Yes. Equality is symmetric, ergo ∀(a, b), if a=b then b=a.
2006-09-08 21:17:38
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answer #1
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answered by Pascal 7
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Of course yes !!!
If expression 1 equals to expression 2,
then expression 2 must equal to expression 1.
Here expression 1 is SineA/a whereas
expression 2 is SineB/b. So they must be equal
to each other.
Whether which one come first and which one come second is NOT important.
You know???
2006-09-09 05:39:49
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answer #2
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answered by Jack 1
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yes, it is the reflexive property of equality.
But if by "Sine Rules" you mean "Law of Sines" and you meant to write:
"...Sin(A)/a = Sin(B)/b...but...Sin(b)/B = Sin(a)/A"
then the answer is no. you can only take sine of an angle not a length.
extra: More specifically, you can only take the sine, cosine, tangent etc. of a dimensionless quantity.
2006-09-09 05:08:16
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answer #3
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answered by cp_exit_105 4
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Not too sure, but isn't it the same equation? Seems like you just changed sides. I mean, if you start with B instead of A, you should get this.
2006-09-09 04:17:38
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answer #4
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answered by astrokid 4
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if, x = y then y = x, this is equality theorem.
Now it does not matter if x and y are any variable, be it Sine, or Cosine. As long as x = y; y must be equal to x, y = x.
2006-09-09 04:45:14
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answer #5
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answered by M1976 2
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we can always say that but as A comes before B we say the above.
It is proper to follow certain guide lines otherwise there shall be confusion.
2006-09-09 04:32:28
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answer #6
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answered by Mein Hoon Na 7
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Ofcorse YES!
2006-09-09 07:55:11
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answer #7
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answered by Anonymous
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Yes.
2006-09-09 07:47:28
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answer #8
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answered by Anonymous
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yeah it is they same. Its like 4x2=8 and 2x4=8.
2006-09-09 04:19:46
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answer #9
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answered by dm_overton 3
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