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5 answers

It can be. Consider the construction (A OR B) AND NOT (A AND B) - this gives you an XOR gate. But note that this construction is not fundamental, we could say that the OR gate is constructed from AND and XOR gates using (A XOR B) XOR (A AND B). Which gates you want to consider "fundamental" and which ones you want to consider "derived" is largely a choice of personal preference.

2006-09-08 21:11:48 · answer #1 · answered by Pascal 7 · 0 0

The answer is yes.
Here is the truth table of XOR gate:
A B O
---------------------------------------
0 0 0
0 1 1
1 0 1
1 1 0

where A and B are input to xor gate
O is output from xor gate
Using Boolean Algebra
O = A'.B + A.B'

where ' is NOT operator
. is AND operator
+ is OR operator
so, you can see that the output of xor gate
is combination of 2 NOT operations, 2 AND operations and one OR operation

2006-09-08 22:34:24 · answer #2 · answered by Jack 1 · 0 0

If you look at the transistor level, it turns out that all of the logic gates are actually made up of a configuration of NAND gates. With NAND gates, you can make all of the other logic gates.

2006-09-08 21:01:42 · answer #3 · answered by Kurt 3 · 1 0

yes it's asking you x or not xor.

2006-09-08 20:53:57 · answer #4 · answered by SivGiger78 2 · 0 0

the answer is yes

2006-09-08 23:36:07 · answer #5 · answered by Anonymous · 0 1

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