a hole of radius r is bored through a cylinder of radius R>r at right angles to the axes of the cylinder. what is the volume of the cut out piece.
2006-09-08 17:17:03 · 6 answers · asked by Will 2 in Science & Mathematics ➔ Mathematics
Ok buddy, Im not gonna give you the answer but i'll give you a hint. Math is a hard thing but you have to put your part so I'll help but you need to do some thinking yourself to understand how and why. This is a pretty tough question and as you know, it is NOT pi(r^2)h as others have listed. Good luck with your homework.
Volume = (8) int (from 0 to r) sqr root of (R^2-y^2)*(r^2-y^2) dy.
2006-09-08 18:03:23 · answer #1 · answered by Zurra V 1 · 0⤊ 0⤋
hole is a cylinder its volume (v) = pi *r^2*diameter of the cylinder v= pi*r^2*(2*R)
2006-09-08 17:44:48 · answer #2 · answered by Dinker 2 · 0⤊ 0⤋
The formula for volume of a cylinder Is: V = Ïr²
2006-09-09 02:25:34 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
gee, did you lose your thinker? if you cannot even spell the question accurately, no wonder you want someone to tell you the answer. do yourself a favor and figure it out....for help, try reading your textbook. it may help you concentrate if you turn off the TV, your cell phone, your music and your computer.
best wishes,
cryllie
2006-09-08 17:22:00 · answer #4 · answered by cryllie 6 · 0⤊ 1⤋
pi*r^2*h
2006-09-08 17:21:38 · answer #5 · answered by _scientist 2 · 0⤊ 1⤋
l(pi)R^2-l(pi)r^2
2006-09-08 17:32:15 · answer #6 · answered by David W 3 · 0⤊ 0⤋