what is the x-intercept?

Question

x (x-1) ^2

would it be 0 and 1?
an explanation would be helpful and thanks for your help.

Answer 1

assuming the equation = y
x intercept is when the x value = 0
so that answer is 0 and 1 but 1 is a double x intercept
since (x-1)^2 = (x-1)*(x-1)
and since the arguments (x, x-1) are multiplying each other all you need to find the x intercept is when one of the arguements = 0
if x=1 x-1 = xero you have your intercept
if x=0 then you have your intercept

but important to know that 1 is a double x intercept.

Answer 2

Yes, the x-intercept is (x, 0).
With f(x) = y = x(x-1)^2, y = 0 when x = 0 or
x = 1.
So, the x-intercepts are 0 and 1.

Answer 3

The question should state what are the x-intercepts because there are two. You get an x-intercept anywhere the equation equals 0. With this equation x=1 and x=0 both satisfy that condition since 1(1-1)^2=0 and 0(x-1)^2=0.

Answer 4

it would be 1

Answer 5

The x-intercepts are found by solving for y=0
The x-intercepts are the "roots" of the equation and in this case, there are two.

y=x(x-1)^2
set y equal to 0
0=x(x-1)^2

root #1: 0=0(0-1)^2=0
root #2: 0=1(1-1)^2=0

so: x-intercepts x=0 and x=1

Answer 6

Both.

A linear equation (ax+b=y) will only have 1 x intercept and 1 y intercept, but x(x-1)^2 is not linear so it can have multiple x intercepts. But all functions will only have 1 y intercept.

Answer 7

(ax+b=y) will only have 1 x intercept and 1 y intercept, but x(x-1)^2 is not linear so it can have multiple x intercepts.

Does your math teacher know about this???

Answer 8

x intercerpt is the value when function f(x) =0
in this case
f(x) = x(x-1)^2 =0
=> x = 0,1,1
so the x intercept is 0 and 1 both

Answer 9

x(x-1)^2..........First take each term and put it equal to zero.......so u have x=0.....(x-1)^2=0.....the first one is already given to u.......x=0.........now look at the second one....square root both sides......so u have x-1=0....and now add one to both sides which will give u x=1......so over all x=0,1

Answer 10

Yes

x(x - 1)^2 = 0

x(x - 1)(x - 1) = 0

x = 0 or 1