A baker needs between 40 lb and 50 lb of a flour/sugar mixture that contains ten times as much flower as sugar. What are the possible weights of flour the baker can use?
I suck at inequality word problems.
2006-09-08 16:29:20 · 4 answers · asked by Poj23 2 in Science & Mathematics ➔ Mathematics
One step at a time. Lets say flour is f and sugar is s. The problem says that the mixture (that's f + s) is between 40 and 50 lbs. So 40 < f+s < 50 ... But ten times as much flour means f = 10s. (Or s = f/10) So make that substitution. I'll let you take it from there.
2006-09-08 16:38:19 · answer #1 · answered by banjuja58 4 · 0⤊ 0⤋
You need 10 units of flour for every one unit of sugar, so the mixture should be 1/11 sugar and 10/11 flour. That means the amount of sugar should be between (1/11)*40 and (1/11)*50 lbs, and the amount of flour should be between (10/11)*40 and (10/11)*50 lbs.
2006-09-08 23:39:30 · answer #2 · answered by Dr. Joe 2 · 0⤊ 0⤋
The flour will be 10/11 of the mixture, so he will need between 400/11 and 500/11 lb of flour.
Use your calculator to get the decimal values
2006-09-08 23:42:49 · answer #3 · answered by Steve 7 · 0⤊ 0⤋
40 <= 10x + x <= 50
40 <= 11x <= 50
The only possible poundage would be 44 lbs, so
40 lbs of flour and 4 lbs of sugar
2006-09-09 00:14:38 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋